Top answers
Maths
A Level
Given that y = 16x + x^-1, find the two values of x for which dy/dx = 0
Expected layout of answer in an exam:y = 16x + x-1dy/dx = 16 - x-2dy/dx = 0 implies that 16 - x-2 = 0this implies that 16 = x-216 = 1/x2
How do I differentiate?
If we have the curve y=x3+3x2-7x+5, to differentiate it we firstly multiply x by its power, and then reduce the power by one.Therefore x3 will differentiate to 3x2
Given y = 2x(x^2 – 1)^5, show that dy/dx = g(x)(x^2 – 1)^4 where g(x) is a function to be determined.
y=2x(x2-1)5dy/dx= 2(x2-1)5 + 2x*10x(x2-1)4dy/dx=(x2-1)4(2x2-2+20x2)dy/dx=(x2-1)
