Top answers

Maths
A Level

Find the tangent to the curve y = x^2 + 3x + 2 that passes through the point (-1,0), sketch the curve and the tangent.

Differentiate to find dy/dx = 3x + 2;at point (-1,0) dy/dx = -1substitute in to y = mx + c, noting m = -1 and the line passes through (-1,0) yields c = -1y = -x - 1, simple to sketch this line.curve sketc...

Answered by Peter W. Maths tutor
2645 Views

Show that cosh(x+y) = cosh(x)cosh(y) + sinh(x)sinh(y)

RHS: cosh(x)cosh(y) + sinh(x)sinh(y) = 1/4(e^x + e^-x)(e^y + e^-y) + 1/4(e^x - e^-x)(e^y - e^-y) = 1/4(e^x.e^y + e^x.e^-y + e^-x.e^y + e^-x.e^-y + e^x.e^y - e^x.e^-y - e^-x.e^y + e^-x.e^-y) = 1/4(2e^x.e^y...

Answered by Alex H. Maths tutor
5213 Views

A curve has equation y = (12x^1/2)-x^3/2

y = 12x1/2 - x3/2
First take the 1/2 power and multiply by the integer in front of the x (so 12 x 1/2 = 6), then minus 1 from the power (1/2 - 1 = -1/2) and replace the power ab...

Answered by Amay B. Maths tutor
4845 Views

Find the stationary point of the function f(x) = x^2 +2x + 5

We can find stationary points of functions by using differentiation, we start this by assessing each term individually, we start with the first term x2, we first start by taking the power term ...

Answered by Henry O. Maths tutor
4935 Views

œintegrate xe4x in respect to x

1/4xe^4x-1/16e^4x +c

Answered by M A. Maths tutor
3348 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences