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Maths
A Level

What is the equation of the tangent at the point (2,1) of the curve with equation x^2 + 3x + 4.

dy/dx = 2x + 3, m = dy/dx = 7 Equation of tangent is a straight line hence we use y-y1 = m(x-x1), y-1 = 7(x - 2), y = 7x - 13

Answered by Bishr A. Maths tutor
3012 Views

How do I find dy/dx for a given equation, once this is found how do I find the value of x such that dy/dx = 0.

From a given equation y = mx + c. Finding dy/dx allows us to see the gradient of the curve. In order to do this we can follow the formula:When y = x

Answered by Sebastian A. Maths tutor
20144 Views

Solve for x (where 0<x<360) 2sin^2(x) - sin(x) - 1 = 0

Factorise the equation (the equation is quadratic in sin(x) )2 sin2(x) - sin(x) - 1 = 0(2sin(x) + 1)(sin(x) - 1) = 0Work out the solutions to the quadratic equation2sin(x) +1 = 0 or ...

Answered by Maths tutor
5000 Views

What is the chain rule?

Up until now you may have been given functions like f(x)= 7x^3 +cos(x) and been told just to differentiate. What your teacher really meant was to differentiate with respect to x. The chain rule allows us ...

Answered by James M. Maths tutor
2412 Views

Find the integral of 4sqrt(x) - 6/x^3.

The easiest way to do this is to break the integral up into it's separate parts. We have:integral of 4sqrt(x)andintegral of -6/x^3
Both of which have constants that can be taken out, i.e. 4 and 6, re...

Answered by Sam P. Maths tutor
2430 Views

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