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The general formula for integration by parts is given as ∫u(dv/dx)dx = uv - ∫v(du/dx)dx given that the equation to be solved is ∫x2sin2xdx, the values for u, v, du/dx and dv/dx can ...
The first thing to do for part a) is work out the vertical component of the velocity. By drawing a triangle where 30m/s is the hypotenuse with angles of 30 degrees, 90 degrees, and 60 degrees, and by appl...
By the power rule, the derivative of x^(n) is nx(n^1) and by the chain rule, the derivative of g(h(x)) is g'(h(x))h'(x). Let g(x)=x^(1/2) and h(x)=3x+2 so that f(x)=g(h(x)).
Then by the power...
You would start with this equation (x – a)2 + (y – b)2 = r2, with the center being at the point (a, b) and the radius being "r". Therefore you would have (x-2)Answered by Ishan N. • Maths tutor4801 Views
First, we need to write cos2x in a form that is easily integrable. We can use the double angle formula cos(2x) = 2cos2x - 1 to see that cos2x = 1/2cos(2x)+1/2. Now, we can...
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