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Let y(x) be a function with derivative y'(x)=x^2-2 and y(0) =7. What is the value of y at x = 3?

Integrate to get y(x) = (1/3)x^3 -2x+c where c is a constant. Substitute in our data 7 =y(0) = (1/3)(0)^3 -2*(0) +c = c. So y(x) =(1/3)x^3 -2x+7 and therefore y(3) = (1/3)(3)^3 -2*3 +7 = 9-6+7 = 10

Answered by Dawn B. • Maths tutor

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Find the area bounded by the curve x^3-3x^2+2x and the x-axis between x=0 and x=1.

To find the area under a curve that is bounded by the x-axis you simply need to integrate the equation of the curve between the limits, so for this equation we will integrate y=x³-3x²

Answered by Jack T. • Maths tutor

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Differentiate ln(x^3 +2) with respect to x

The differential of ln(x) is x^-1 or 1/x. Because we have x^3 + 2 inside the bracket we have to differentiate this term also and multiply this with the other term. For example, d/dx of x^3 +2 is equal to ...

Answered by George L. • Maths tutor

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A curve is defined by the parametric equations: X = 3 – 4t , y = 1 + (2/t) Find (dy/dx) in terms of t.

When dividing fractions by fractions with a common factor:

(a/c) / (b/c) = (a/c) * (c/b) = (ac/bc) we can cancel the common factor to get (a/b).

So in this question we can do the same:

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Answered by Eddie E. • Maths tutor

5658 Views

integrate cos(2x) + sin(3x)

the differential of cos(x) is -sin(x). the differential of cos(2x) is -2sin(2x). you can think of it as differentiating what is in the bracket and putting that in front of the -sin(2x). when differentiati...

Answered by Ajay D. • Maths tutor

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