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Find dy/dx at t=3, where x=t^3-5t^2+5t and y=2t^2

Using the product rule, we find that dy/dx= dy/dt multiplied by dt/dx, where dt/dx is the reciprocal of dx/dt

dx/dt= 3t^2-10t+5, dy/dt= 4t

At t=3, dx/dt= 3(3)^2-10(3)+5=2, dy/dt= 4(3)= 12

Answered by Oore A. • Maths tutor

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Express 21/root7 in the form k root7.

21/root 7 = 21root7/7 = 3root7

k = 3

Answered by Ally W. • Maths tutor

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Given that y = 5x(3) + 7x + 3, find A) dy/dx B) d2y/dx2

A) 15x² +7

B) 30x

Answered by Ally W. • Maths tutor

4506 Views

Given y = 2x^2 + 3x + 2 find dy/dx

To get dy/dx from a formula y in terms of x we must differentiate y with respect to x. Generic formula for term differentiation: d/dx(ax^b) = bax^b-1 = times the coefficient by the power and minus the pow...

Answered by Alex O. • Maths tutor

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Given that 4 sin(x) + 5 cos(x) = 0 , find the value of tan x .

Before we get started with answering the question, it is generally good practice to write down any formulas and equations you know that will help us work through the solution. So what formula do we know t...

Answered by Varun C. • Maths tutor

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