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First we must differentiate the equation with respect to x. To differentiate you must multiply the coefficient (number in front) by the power of x, then subtract 1 from the power. So here we find dy/dx = ...

3x² + 2x + 4

Starting with ∫a^x dx ,
We can re-write a^x using logs as e^ln(a)*x using some of their properties
We use the substitution u = ln(a)*x (as such du/dx = ln(a)) all...

You start by seperating the variables giving,

(1/x)*dx=(-6)*dt

you then integrate both sides with respect to the variables,

ln(x)=-6*t+c

you then subsitute in the given conditi...

x^3/3  +  1/x