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We want a solution to ax^2+bx+c=0. Complete the square to get a[(x+b/2a)^2 -(b^2)/(4a^2)]+c=0. Expalding brackets and rearanging gets a(x+b/2a)^2=(b^2)/4a -c. Divide by a to get (x+b/2a)^2= b^2/4a^2 -c/a=...
Solution:
V = V(0) + a*t
From the question: a = (-3i + 12j); Answered by Artur R. • Maths tutor5868 Views
The differential of a function is defined by the expression: dy/dx = Lim(dx->0) of (f(x+dx)-f(x))/dx. For functions only involving powers of x, the differentioal can easily be calculated by timesing by...
Let eqn. 1 be: 3x + 2y - 1 = 0 & Let eqn. 2 be: 4x - 6y -10 = 0
Multiply eqn. 1 by a factor of 3, and add the two eqautions together. (This eliminates y from the equation)
This gives: 9...
M=3
y1=1
x1=2
y-y1=m(x=x1)
y-1=3(x-2)
y-1=3x-6
y=3x-6
at the x axis, y=0.
‘Sub in to find the x co-rdinate:
0=3x-5
...
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