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Differentiate the original equation (y = x^2) to find the gradient (m) of the line which is a tangent to the curve.
Dy/dx = 2x
Therefore m = 2
Calculate the negative reciprocal (m2) ...
From reading the question, we need to use the addition formula for sin(A+B)= sinAcosB+cosAsinB. So we need to think what are two common values for sine and cosine that we know and have exact answers for t...
Equation of a circle -> (x-a)2 + (y-b)^2 = r2 where the centre = (a,b) and the radius = r
Thus using the equation above we can conclude that the centre is (2,-5)
This question might look hard but can be easily answered by breaking it down into steps and remembering a few key things. The first step is to recognise that the question is mentioning a stationary point ...
4cos2 x + 7 sinx - 7 =0 we know that sin2 + cos2 = 1 so 4(1-sin2x) + 7sinx -7 = 0 if we times out the brackets -4sin2x + 7 sinx -3 =0 4sin2Answered by Jo P. • Maths tutor3155 Views
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