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In most core 1 papers this kind of question is usually asked. First of all an asymptote is a line that is close to an axis but never touches it. Now look at the graph as a normal reciprocal graph of y=1/x...
Using the product rule we know that dy/dx = uv' + vu' where u = 3x^3; v = e^x. e^x differentiates to itself multiplied by any number in front of the x. u' = 9x^2; v' = e^x. Therefore dy/dx = 3x^3e...
when integrating with the limits, you substitute in the two limits into the integral and then take them away. As both will have added the constant 'c', you are taking c away from c and so cancel out, so i...
F(x+2) is simply F(x) but whenever you see an 'x' replace it with 'x+2'. So when x is say 3, F(x) is F(3) and F(x+2) is F(5). If we draw this out on a graph, we see that this has the effect of shifting th...
The minimum point occurs where dy/dx=0
We have 2 options: 1.) Expanding the brackets 2.) The product rule of differentiation
The shortest is the product rule: dy/dx= (d/dx)(3-x).(x2Answered by Zita E. • Maths tutor2675 Views
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