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Maths
A Level

How do I find the equation of a tangent to a given point on a curve?

Let's take an example: Curve: y = x^2 Point: (2,4)

The equation of the tangent is going to be of the form y = mx + c (standard equation of a straight line), where m is the gradient of the line ...

Answered by Theo P. Maths tutor
3487 Views

The line AB has equation 3x + 5y = 7, find; a) the gradient of AB b) the x-axis and y-axis intercepts c) sketch the graph

a) Rearrange equation into the form y = mx + c where m is the gradient and c is the y-axis intercept. Gradient AB = -3/5. b) The y-intercept is c which = 7/5. To find x-axis intercept we set y=0 and rearr...

Answered by Will H. Maths tutor
4244 Views

Simplify: (3x+8)/5 > 2x + 1

  1. Multiply both sides by 5: 3x + 8 > 10 x + 5
  2. Move 3x to RHS by subtracting 3x from both sides: 8 > 7x + 5
  3. Move 5 to LHS by subtracting 5 from both sides: 3 > 7x
  4. Ma...
Answered by Orlaith D. Maths tutor
3941 Views

Differentiate: 2(x^2+2)^3

This is a chain rule question. Unlike in ordinary differentiation we have more than just the single term 'x' with coefficient 1 raised to the power of something. e.g. x^3 Therefore, there is more steps. W...

Answered by Charlotte A. Maths tutor
2798 Views

Sketch the graph of x^2+y^2-6x-4y=23

Firstly, to try and sketch this graph just going on the equation as it is above is a huge task for any maths student. The best way to approach this is to neaten it up with some algebra:

-1: x^2+y^2...

Answered by Sam A. Maths tutor
7794 Views

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