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This is like solving 2 simultaneous equations. Both equations are in a form of y=ax^2+bx+c. Equate both equations together and you got: 3x2+5x+12 = 3x-8
Put both polynomi...
A neat trick to remember what we do to the powers when integrating and differentiating is that we INcrease the power when we INtegrate, and D...
This is one of the trickiest methods of calculus on the course, but it's important to know, and is very doable if you set up the problem right and remember the steps.
Integration by part...
Every point on the curve C satisfies the equation. In order to show P lies on C, we need to test if either x- or y-coordinates satisfy the equation. It is easier to subsitute x=2 into the equation.
Starting with the initial integral of int(exp(x).cos(x))dx we can see that this is going to have to be integrated by parts. This states that the integral of (u . dv/dx)dx is equal to u.v - int(v . du/d...
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