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Maths
A Level

Differentiate with respect to x: x*cos(x)

Firstly, xcos(x) is a product of two functions of x. Therefore we can use the product rule to work out the derivative of the whole function. Differentiating each part makes it easier to visualize the ...

Answered by Stefan S. Maths tutor
2694 Views

Prove cosec2A-cot2A=tanA

Cosec2A - cot2A= tanA
Left hand side=1/sin2A - cos2A/sin2A
=(1- cos2A)/sin2A
=(1-(1- 2 sin^2⁡ A)/ 2sinAcosA
=(1-1 + ( 2 sin^2⁡ A))/ 2sinAcosA
=sinA/cosA
=tanA
Therefore ...

Answered by Sherin T. Maths tutor
11210 Views

A curve is defined by parametric equations: x = t^(2) + 2, and y = t(4-t^(2)). Find dy/dx in terms of t, hence, define the gradient of the curve at the point where t = 2.

dy/dx = (dy/dt)/(dx/dt) y = t(4-t2 ), then using differentiation of y with respect to t, dy/dt = 4 - 3t2x = t2 + 2, then...

Answered by Micah W. Maths tutor
4486 Views

Express 3sin(2x) + 5cos(2x) in the form Rsin(2x+a), R>0 0<a<pi/2

Start by expanding out Rsin(2x+a) using the addition formula for sin, sin(A+B) = sin(A)cos(B)+cos(A)sin(B). Substituting 2x = A and a= b, we get that Rsin(2x+a) = R(sin(2x)cos(a) + cos(2x)sin(a)) = Rcos(a...

Answered by Michael F. Maths tutor
8141 Views

Solve the simultaneous equations: y=x+1, x^2+y^2=13

We already have an expression for y, so we can substitute this in:x2+(x+1)2=x2+(x+1)(x+1) = x2+x2+2x+1=2x2+2x+1 and hence 2x2+2...

Answered by Lauren C. Maths tutor
6021 Views

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