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Maths
A Level

A circle with centre C has equation x^2 + y^2 +8x -12y = 12

Recognise that the form this question is a circleRemember alternate circle equation (x + a)2 + (x + b)2 = r2Where centre of circle (-a,-b) and r is the radiusTo get the ri...

Answered by Monique G. Maths tutor
2918 Views

Differentiate the equation y = (2x+5)^2 using the chain rule to determine the x coordinate of a stationary point on the curve.

Use the chain rule as this is a composite function. Let u=2x+5.So the original equation becomes y=(u)^2.Using the chain rule: dy/dx = dy/du * du/dxdy/du = 2udu/dx = 2So dy/dx= 4uSince u=2x+5, dy/dx = 4(2x...

Answered by Daniel P. Maths tutor
4377 Views

Show that 2sin(x) =(4cos(x)-1)/tan(x) can be written as: 6cos^2(x)-cos(x)-2=0

Rearranging gives:4cos(x)-1 = 2sin(x)tan(x) Substituting in tan(x)=sin(x)/cos(x) gives:4cos(x)-1 = 2sin(x)(sin(x)/cos(x))2sin2(x)=4cos2(x)-4cos(x)Substituting in 2sin2<...

Answered by Olivia T. Maths tutor
15098 Views

The General Form of the equation of a circle is x^2 + y^2 + 2gx +2fy + c = 0. Find the centre of the circle and the radius of the circle in terms of g f and c.

Given a circle in the general form you can complete the square to change it into the standard form.x2 + 2gx + y2 +2fy +c = 0 (1). General form of an equation which has the completing...

Answered by Rushabh S. Maths tutor
5281 Views

a) Integrate ln(x) + 1/x - x to find the equation for Curve A b) find the x coordinate on Curve A when y = 0.

a) Integrate ln(x) by parts: u = ln(x), dv/dx = 1, du/dx = 1/x, v = x int(udv/dx) = uv - int(du/dx * v) = ln(x)/x - x so int(ln(x) + 1/x - x) = ln(x)/x - x + ln(x) + x^2 + Cb) y = ln(x)/x - x + l...

Answered by Ellie N. Maths tutor
2369 Views

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