Top answers

Physics
A Level

Difference between compression ignition engine and a spark ignition engine

The cycle of compression in both the engines are different in the thermodynamic terms. The spark ignition engine is a gasoline or petrol engine which is based on the otto cycle. It uses a spark generated ...

Answered by Wajih M. Physics tutor
4039 Views

From the definition of the decay constant for nuclear decay, derive the exponential decay equation.

By definition, dn/dt = - λ N ,
If you separate the variables which contain N and t, and then integrate w.r.t N and w.r.t t you get,
lnN = -λt + C (1),
...

Answered by Jake P. Physics tutor
1722 Views

A ball is thrown vertically downwards at a speed of 10ms^-1 from a height of 10m. Upon hitting the floor 10% of the energy is dissipated through waste heat. What is the heighest point the ball reaches before it comes to rest? Take g=10ms^-2

The first step is to calculate the initial energy of the system. at the moment of throwing. Energy is comprised of both potential (given by Mgh) and kinetic(given by 0.5Mv^2), and so the initial energy is...

Answered by Russell J. Physics tutor
1324 Views

A) Draw field lines around a positive point particle. B) How does a faraday cage prevent the people within it recieving a electric shock ?

A) symmetrical straight lines coming out of the particle, with arrows pointing away from the particle. A useful tool in answering these questions is to imagine what would happen if you placed a second pos...

Answered by Thomas H. Physics tutor
1313 Views

A guitar string 0.65m long vibrates with a first harmonic frequency of 280Hz. Mary measures 1m of the string and discovers that it weighs 8.0x10^-4 kg. What is the tension in the guitar string?

f = 280 Hz, l = 0.65 m, μ = 8x10^-4 kgm^-1Therefore use the equation f=(1/2l)(T/μ)^1/2Rearrange it to get it in the form T= by multiplying f by 2l, squaring both sides and then multiplying by μ to getT = ...

Answered by Evie S. Physics tutor
1689 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences