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Maths
GCSE

Solve the following simulatenous equation to find the values of both x and y: 5x+2y=16 3x-y=14

x=4, y=-2

Answered by Oliver G. Maths tutor
2644 Views

Solve the following ((3x + 1)/2x ) = 4

3x + 1 = 4(2x) 3x + 1 = 8x 1 = 5x x = 1/5

Answered by Benjamin L. Maths tutor
3711 Views

How do you divide mixed fractions? e.g. (1(1/5)) / (3/4)

(1(1/5)) / (3/4)1(1/5) = 6/5therefore the question is(6/5) / (3/4)To divide a fraction, you simply swap the position of the numerator and denominator in the latter part of the example, and multiple the fr...

Answered by Jack M. Maths tutor
2483 Views

Solve the simultaneous equations, x+y = 16, 5x -2y = 17

Multiply the first equation by 2 to obtain 2x+2y = 32,Then use the elimination technique and add the first equation into the second equation to get : 7x = 49 therefore divide by 7 to find x = 7 Sub this v...

Answered by Matthew O. Maths tutor
3229 Views

Expand and simplify (x+1)(2x+3).

We first expand the first set of brackets by multiplying each element of it by the second set of brackets so (x + 1)(2x + 3) = (x)(2x + 3) + (1)(2x + 3) = x(2x + 3) + (2x + 3). We can then expand out the ...

Answered by Matthew L. Maths tutor
7458 Views

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