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Maths
GCSE

Solve y=x^2 - 1, y=5 - x

x= -3, y= 8 and x= 2, y= 3
(1) 5 - x = x^2 - 1(2) x^2 + x - 6 = 0(3) (x+3)(x-2) = 0(4) when x = -3, y= 5 - (-3) = 8(5) when x = 2, y= 5 -(2) = 3

Answered by Tamim B. Maths tutor
2750 Views

What is Pythagoras' Theorem and how do I use it?

Pythagoras' Theorem is used to find the length of the hypotenuse (longest side, opposite the 90 degree angle) of a right angled triangle when the length of ...

Answered by Sophie T. Maths tutor
2346 Views

Solve the Inequality X^2 - 2X - 8 < 0

First we need to solve the Inequality, looking at what two numbers add to give -2 and multiply to give -8 we find these to be -4 and +2. So we can now say that (X-4)(X+2)<0. Then I like to draw a ...

Answered by Liam C. Maths tutor
5537 Views

AQA, foundation 2016: Lee does a sponsored silence for 2.25 hrs. He is sponsored 80p per minute. How much does he raise?

80p every minute.So how much in 15 mins?How much in an hour?What operation do we use?Easy way to do mental maths - break it up!2.25hrs = 1hr + 1hr + 15 mins80p60 + 80p60 + 80p*15?= 4800p + 4800p ...

Answered by Garima A. Maths tutor
2338 Views

OCR, 2016, Higher Maths: Rationalise the denominator 1/(1+sqrt(3))

First make sure they know are clear on what a rational number isAsk them to try multiplying 1 + sqrt(3) by different values to see how to make it a rational numberE.g. they might try (1+sqrt(3))2

Answered by Garima A. Maths tutor
2454 Views

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