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Rectangle ABCD has sides 2x+5 and x+2 with rectangle EFGH of sides x+3 and x cut out of it. The total area of shape ABCD is 5cm^2. Show that 0 = x^2 + 6x +5 [5 Marks]

Area of ABCD = (2x+5)(x+2) = 2x² +9x +10Area of EFGH = (x+3)(x) = x² + 3xTotal Area = 5 = ABCD - EFGH = 2x² +9x +10 - x² - 3x 5 = x² + 6x +10 0 = x

Answered by Arad S. • Maths tutor

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How do you factorize a quadratic when a ≠ 1 when ax²+bx+c=0

First check if a, b and c all have a common factor.For example, if we have 3x²+6x+3=0, we can divide both sides by 3 and get x²+2x+1=0, which is easier to solve.If a,b and c do not all have a common facto...

Answered by Gabriel Thomas N. • Maths tutor

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Solve the simultaneous equation by elimination: 3x + y = 11 and 5x + y = 4

Simultaneous equations have at least two unknowns that must have the same value in each equation. This means the value of x and y in both equations must...

Answered by Moyin A. • Maths tutor

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How do you translate the graph y = x^2, five unit squares negatively horizontally and 3 unit squares positively vertically?

Start again by drawing the graph and then the translated graphExplain what is meant by a translation ( a movement of the graph )Use a table of values to show how we can change the function to allow for di...

Answered by Harrison L. • Maths tutor

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