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The width of a rectangle is X cm.  The length is 1·5 cm more than the width.  The perimeter of the rectangle is 17 cm. Write down an equation satisfied by X  and solve it to find X.

Let's call the length 'L', and the width 'X'. Since the length is 1.5cm more than width, we can form the equation: L = X + 1.5 (Equation 1)Let's call the perimeter 'P'....

Answered by Oliver D. • Maths tutor

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Write the following in their simplest form: a) 8^0 b) 64^(2/3) c) 0.54545454...

a) 8⁰= 1b) 64^2/3 = (64^1/3)² = 4² =16c) 0.54545454... = x 100x = 54.545454.... 100x-x = 54 99x = 54 x = 54/99 x = 6/11...

Answered by Emmanuel S. • Maths tutor

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Solve the simultaneous equations: 5x+5y = 6 7x+3y = 6

Label the equations 1) 5x+5y = 6 and 2) 7x+3y = 6 . Then rearrange equation 1 to make x the subject of the equation: 5x = 6-5y. You would then simplify this equation to find the equation for x: x = 6/5 - ...

Answered by Isobel B. • Maths tutor

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