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Solve the quadratic equation, x^2 - 4x -5 = 0

Solve x²- 4x - 5 = 0
A very full explanation would be:
Start by listing the pairs of numbers that can be multiplied together to get 1 * -5 = -5 (i.e. the coefficient of the first ter...

Answered by Ryan H. • Maths tutor

3814 Views

Solve for y and x, where x=y+1 and y=2x+3

Simultaneous equations:
x=y+1 y=2x+3
First solve for x. y=2x+3 so first equation becomes: x=(2x+3)+1 x-2x-3-1=0 -1x-4=0x+4=0 x=-4
Solve for y: y=2x+3 y=2(-4)+3 y=-8+3y=-5

Answered by Tom S. • Maths tutor

3359 Views

Solve the simultaneous equations 2x + y = 7 and 3x - y = 8

There are three methods for solving simultaneous equations: elimination, substitution and by using graphs.Elimination is a good method in this case as the y terms are equal in both equations. We just add ...

Answered by Tia J. • Maths tutor

6566 Views

How do you solve the simultaneous equations x^2+y=1 and -x+y=-1

First rearrange the second equation so that it's equal to y. You do this by adding x and y to both sides of the equation. You should then have y=x-1. Next you should sub y=x-1 into the first equation, x

Answered by Chloe M. • Maths tutor

2632 Views

Make x the subject of, 4(x+1)/(x+2) = y

The fundamental rule to keep in the back of your head is 'whatever happens to one side must happen to the other'. This way we can be sure that whatever is on the left hand side of the equals sign will be ...

Answered by Jack W. • Maths tutor

4107 Views