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Maths
GCSE

A right angle triangle has a base of √8 and a height of (√10+3). Show that the area is equal to 2√5+3√2.

The area of a triangle is equal to 1/2 x base x height, so we can write the equation for this question as: Area = 1/2 x √8 x (√10+3) We can then simplify √8 by writing it as its fa...

Answered by Elizabeth H. Maths tutor
3643 Views

solve the simultaneous equations 3x+7y=18 and 7x+9y=8

3x+7y=18 (eqn 1)  -multiply by 7->   21x+49y=126 (eqn 1*)

7x+9y=8  (eqn 2)  -multiply by 3->    21x+27y=24 (eqn 2*)

(eqn 1*)-(eqn 2*)  --> 22y=102 therefor y=51/11

sub in thi...

Answered by Radhika S. Maths tutor
3021 Views

Solve the following simultaneous equations: (1) 4x+y=7 and (2) 3x+2y=9

This question can be answered by the elimination method. I will choose to eliminate 'y' in this case. Firstly, multiply equation (1) by 2, resulting in 8x+2y=14. Now we can subtract eqaution (2): 3x+2y=9 ...

Answered by Alex D. Maths tutor
5077 Views

Solve for x: 4 x + 1 = 2 x + 12

The best way to answer these kind of questions is by moving all the unknowns to one side. In this case, the only unknown is x, so we should start by moving all the x's to one side. Since there are 4x's on...

Answered by Tejas K. Maths tutor
2796 Views

X is a prime number higher than the square of 5 and lower than the square of 7. What are the smallest and largest possible values for X?

The square of 5 is 25 and the square of 7 is 49. The prime numbers found between these 2 values are: 29, 31, 37, 41, 43 and 47. This means the smallest value fitting the criteria is 29 and the largest val...

Answered by Oana C. Maths tutor
2660 Views

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