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A student will often see the equation of a circle in the form (x-a)²+(y-b)²=r². In this instance, a and b simply represent numbers. They are not variables. In fact, a repr...

To solve an algebraic equation you need to rearrange it into the format x=? To do this there are a few rules and few steps

Rules:

• wh...

Firstly, begin by multiplying both sides of the equation by (x-2) and (x+3), this gives 6(x+3)-2(x-2)=(x+3)(x-2). Expand out the brackets on each side of the equation to give 6x+18-2x+4=x²-2x+3...

(1) x² + 15x + 56 = 0

56 = 1 x 56, 2 x 26, 4 x 14, 7 x 8

7 + 8 = 15

Hence, factorised equation is (x + 7)(x + 8) = 0

First, expand (x-2)²:

= (x-2)(x-2),

= x² - 2x - 2x + 4

= x² - 4x + 4

Add on the +7:

= x² - 4x + 11

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