Top answers

Maths
GCSE

How do I solve an equation where there are unknowns on both sides of the equation?

Golden rule: Do the Same thing to both sides of the equation Approach in 4 steps 1) Multiply out any brackets 2) Gather the like terms (Use analogy of apples and oranges) 3) Get all unknown terms to one s...

Answered by Chris B. Maths tutor
3086 Views

A cuboid has sides such that the longest side is two units more than the shortest side, and the middle length side is one unit longer than the shortest side. The total surface area of the cuboid is 52 units². Calculate the length of the shortest side.

The sides of the cuboid are as follows: x, x+1 and x+2. Total surface area of a cuboid is the area of each surface added together. Therefore 2x(x+2)+2x(x+1)+2(x+2)(x+1)= 52 units².

2x²+4x+2x²+2x+2x...

Answered by Sabina S. Maths tutor
2870 Views

Make n the subject of the formula: m = 5n - 21

The answer is: n = (m + 21)/5 How did we get this? Right now, the equation is written in the form where m is the subject. We want to rearrange this so that n is the subject of the formula. The formula sho...

Answered by Jabin C. Maths tutor
18497 Views

A right angled triangle has 2 known sides measuring 3 meters, 4 meters respectively. Find the hypotenuse and the smallest angle in the triangle.

This is an example of a pythagoras. The student has to use the knowledge that the hypotenuse (longest side) is the square root of the sum of the squares of the known sides. In this instance, it would be 4...

Answered by Zara M. Maths tutor
4009 Views

Find x and y when 3x + 4y = 27 and x + 2y = 11

Use the elimination method to remove a common coefficient.

Multiply one of the equations to find a common coefficient, eg multiply the second equation by 2 to get 2x + 4y = 22, to reach the common ...

Answered by Eleanor S. Maths tutor
5690 Views

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