Search over 10,000 free study notes

Since there is no further factorisation possible we use the quadratic formula x=[-b±√(b²-4ac)]/2a. From the equation in question we have  a=3, b=-7, c=3. Substituting into the quadratic formula...

2x² - x - 6 = 0

This must first be factorised - I use the 'box method' when the reciprocal of x² is >1. This is difficult to explain via writing but it inv...

This equation is asking us to find the value(s) of x that when substituted in place of x in the equation x²-4x+3 the computed value should equal 0. There three potential methods of solving this...

In order to solve the quadratic, we need to factorise it. Consider the coefficient on the x^2, its only factors are 1 and 3 so this tells us that in our factorising we will have something that looks like ...

Label your equations 1 and 2 respectively. Make y the subject of equation 2 by taking away 3x from both sides and multiplying both sides by -1, to get y = 3x - 8. Now substitute this into equation 1 (i.e....