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I'd start by drawing out any rectangle with an area of 20cm^2 and labelling the length and width. Any correct combination will do (i.e. 2 X 10, 4 X 5, 20 X 1 etc.). In this example, I will use 4 X 5 Then ...
There are two ways to solve this equation. In the first method, we can simplify the quadratic by observation into two linear equations multiplied together, giving us (2x + 1)(x + 1) = 0. We can then set e...
By the quadratic formula, where a = 3, b = 5, c = 2 x = -2/3 and x = -1
(7,0)
Firstly, take the second equation and make either x or y the subject, which means to make it either x equals or y equals. To make x the subject, we take y away from both sides giving x=8-y. Then, substitu...
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