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Solve the simultaneous equations: y=x/2 + 2 and 2y+3x=12

Label the equations (1): y=x/2 + 2 and (2): 2y+3x=12. Firstly, multiply equation (1)by 2, this will give you (1a): 2y=x+4, then, substitute (1a) into (2). This gives you (x+4)+3x=12. Therefore, 4x+4=12. 4...

Answered by Joseph B. • Maths tutor

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Solve the equation x^2-9x+20=0

First, we need to factorise the equation on the left hand side, this can be done by finding two numbers that add together to make the 'b' coefficient (-9) and multiply to make the 'c' coefficient (20).

Answered by Joseph B. • Maths tutor

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Simplify 3x^(2)+13x-30/x^(2)-32

First of all spot that the bottom of the fraction is a result of the difference of two squares and can be rearranged to (x+6)(x-6), making the fraction equal to 3x^(2)+13x-30/(x+6)(x-6). Use this knowledg...

Answered by Nicolaas P. • Maths tutor

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Solve (4-2x)/(x+1)=x

To solve this equation, we need to collect all of the x^2 terms and the x terms together. To do this we should start by getting rid of the fraction on the left-hand side by multiplying both sides by the d...

Answered by Emily K. • Maths tutor

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