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The method we shall use is substitution. We shall replace y each term by 'x + 1' so we are able to obtain an equation in one variable. x^2 + (x+1)^2 + 18x + 20(x+1) + 81 = 0. We now expand the brackets. x...

Multiply through by both denominators, giving us the equation (2x + 3)(2x + 1) - (2x - 8)(x - 4) = (x-4)(2x +1). If we expand the brackets, we arrive at 4x^2 + 8x + 3 - (2x^2 -16x + 32) = 2x^2 -7x -4. If ...

Here we have a pair of simultaneous equations with two unknowns. There are two methods of going about this question: substitution or elimination. Today, we shall be focusing on the latter. We need a pair...

When we are asked to solve a quadratic, we can use the formula, but we are here specifically asked to use factorisation.

First of all, we need to know the format of factorisation: usually, it's (x+...

In order to solve this question, I am going to use the FOIL (first, outer, inner, last) method of expanding brackets. First we need to multiply the two first elements in each bracket together - in this ca...