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Maths
GCSE

Solve the simultaneous equations y=2x and y=x+3

As both equations have y on the left hand side we can put the right hand sides equal to each other, so 2x=x+3. We can then subtract x from both sides. This gives 2x-x on the left hand side which is x, and...

Answered by Hannah C. Maths tutor
7751 Views

Sketch a graph of the equation of y=3x+2

Looking at this equation you can see that it is in the form of y = mx + c and we know that this is the equation of a straight line. One way to solve this would be to inspect the equation and see that the ...

Answered by Hannah B. Maths tutor
6194 Views

Rationalise the denominator of the fraction 3/sqrt(5)

In order to rationalise the denominator we need to get rid of the surd (square-root) on the bottom of the fraction.

To do this, we can multiply the denominator by sqrt(5).

But we must notice...

Answered by Murray M. Maths tutor
17217 Views

Does the function y=x^3+x+(x^2+1)e^x have a horizontal tangent?

We want to determine whether a function has a tangent which is horizontal. To answer the question we need to know what a horizontal tangent to a function means. A tangent to a graph of a function is a lin...

Answered by Daniel E. Maths tutor
6059 Views

Solve the simultaneous equations: y=5-x and y=x+1.

Since y is equal to both 5-x and to x+1, we know that 5-x is equal to x+1. We can write 5-x=x+1. Take 1 away from each side: 4-x=x. Then add x to each side: 4=2x. Divide both sides by 2: 2=x. Now we have ...

Answered by Charlotte W. Maths tutor
17244 Views

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