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The objective of this question is to solve for x and y. Since we cannot directly eliminate x or y, find the lowest common multiple for x in both equations by comparing 2x in equation 1 with 6x in equation...

First of all remember to never be intimidated by a question. Don't read a question and say "I don't know," start with what you do know. In this case we know that every year the £12,00 initial va...

I like to address this question by using similar fractions. That is to say x/y=2x/2y X over y is the same as 2x over 2y In this example we are asked what the full price of the dress is, as in what 100% of...

General rule for any right angled triangle: a^2+b^2=c^2, with a and b being the shorter sides and c being the hypotenuse (the longest side). Using the equation: a=7 and b = 11 and c=hypotenuse we want to ...

(1) Get rid of the fraction by multiply both sides by (4-x), we now have y(4-x)=3x+5. (2) Expand any brackets, so 4y-py=3x+5. (3) Rearrange to get all the x to one side: 4y-5=3x+px. (4) Factorise x becaus...