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Maths
GCSE

(2x + 3y)^2 – (2x – 3y)^2 = 360 show that xy is a multiple of 5

Expand first brackets:

4x2+6xy+6xy+9y2

Expand second brackets:

4xy2-6xy-6xy+9y2

Subtract the second e...

Answered by Ryan M. Maths tutor
8947 Views

Solve the simultaneous equations 5x + 3y = 24 and 3x - 4y = 26

Ok, so here are the equations5x+3y=243x-4y=26So let's multiply the first equation by 3, which gives us:15x+9y=72Now let's multiply the second equation by 5, which gives us:15x-20y=130So we're now left wit...

Answered by William S. Maths tutor
10636 Views

How do I solve x^2+6x+8=0?

Ok, so we would call this a quadratic equation because it is written in the form of ax^2+bx+c=0 (in our case, a=1, b=6, c=8).Luckily, this type of quadratic equation can be factorised, so we can solve it ...

Answered by William S. Maths tutor
13949 Views

Solve the simultaneous equations y = 2x-3 and x^2 +y^2 = 2

Let the first equation be equation 1 and the second equation be equation 2.

Firstly, you must substitute equation 1 into equation 2. This is because there are currently two unknown values...

Answered by Daniel D. Maths tutor
27646 Views

Solve for x: 2x^2 + 7x + 6 = 0

Solve for x: 2x2 + 7x + 6 = 0

The first thing to do is look at the left hand side and factorise it. To do this we use the reverse of FOIL. Then when the expres...

Answered by Asher C. Maths tutor
18306 Views

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