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The graph of y = x^2 – 1 is translated 3 units to the left to give graph A.The equation of graphA can be written in the form y=x^2 +bx+c Work out the values of b and c.

identify what the question is asking -> both translation rules and expansion of bracketstranslation rule --> translation of 3units left on x-axis actually gives a the graph of y=(x+3)^2 -1. This is bec...
GP
Answered by Georgia P. • Maths tutor
8601 Views

Solve simultaneously: 3x+2y=7 & x-2y=-3

Add the 2 eqns together to eliminate the y's to give: 4x=4. Divide by 4 to give x=1Now substitute x=1 into the first eqn: 3+2y=7. Subtract 3 from both sides -> 2y=4. Divide by 2 to give y=2.Now, check by ...
KL
Answered by Katie L. • Maths tutor
5556 Views

Find the coordinates of the turning point of the graph y=x^2 -x -12. Use it to sketch the graph on a set of x-y axis.

-Firstly we should check if the equation has the variables separated (x on one side and y on the other side of the equal sign), which they apear to are, therefore we can proceed to the next step. As it is kn...
IP
Answered by Ioanna P. • Maths tutor
7047 Views

solve 15x = 6x^3 + 8x^2

6x 3 + 8x 2 -15x = 0x(6x 2 + 8x - 15) = 0x=06x 2 + 8x - 15 = 0Quadratic formula ( can demonstrate in interview)x = 0 or x = 1.049 or x = -2.38
LL
Answered by Lewis L. • Maths tutor
3174 Views

find the second degree equation that passes through the points: (0,1) (2,2) (1,0)

first of all we have to recognise the general form of the equation, similar to the equation of a line but we just have to add one more term due to the fact that it is a second degree equation: y=ax 2 +bx+c. ...
LG
Answered by Luca G. • Maths tutor
3626 Views