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Maths
GCSE

find the equation of the tangent to the curve y=2x^3+3 at the point where x= -2

know to differentiate to find the gradient of the tangent: y=2x3+3, dy/dx= 6x2When x=-2, dy/dx= 24When x=-2, y=2(-2)3+3, y= -13equation of a tangent is y=mx+c, where y=-13...

Answered by David H. Maths tutor
4180 Views

P is (4, 9) and Q is (–2, 1); calculate the midpoint of PQ.

for the x coordinate; 4+(-2)=2 divide by two to find where midpoint between the two x coordinates 2/2=1for the y coordinate; 9+1= 10divide by 2 to find the midpoint between the two y coordinates 10/2=5the...

Answered by Alexander R. Maths tutor
6099 Views

Factorise and solve for the solutions of X in the equation X^2 + 8X +15?

Think of 2 numbers that will add up to give you 8 and mutiply to give you 155 and 3!(X+3)(X+5)=0Anything multiplied by 0=0 so the trick is to make each bracket be equal to 0X+3=0Therefore X=-3X+5=0Therefo...

Answered by Stephen S. Maths tutor
2240 Views

solve the simultanious equations: x - 2y = 2 and 2x + y = -1

I would first isolate x in the first equation in the left hand side (x = 2 + 2y). Then I would replace the x in the second equation with the right hand side of the first equation, making the second equati...

Answered by Pedro S. Maths tutor
2947 Views

Factorize 2(x^2) - 2x - 12 fully

2(x2) - 2x - 12= 2( x^2 - x - 6)The constant is negative so the 2 factors must have opposite signs. Then, the x term is negative so the larger one must be negative, and the smaller one positive...

Answered by Danielle H. Maths tutor
2441 Views

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