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The curve and the line will intersect when the two expressions are equal, so:4x2+ 5x + 3 = x + 2 (eliminating y and putting the expressions in terms of one variable).4x2+ 4x + 1 = 0(...
6x2 + 4x - 10 = 06x2 + 10x - 6x - 10 = 02x(3x + 5) - 2(3x + 5) = 0(2x - 2)(3x + 5) = 0Case 1: 2x - 2 = 02x = 2x = 1Case 2: 3x +...
Evaluate each bracket first. We have:(2a + a)x(5a - a) = (3a)x(4a)Then, multiply both brackets.(3a)x(4a) = 12a2
(6(x+4) + x(x-3) )/ ((x-3)(x+4)) = 1 obtain a common denominator and write as one fraction. (6x+24+x2-3x ) /( x2-3x+4x-12) = 1 multiply out the brackets. (x2+3x+24)/ (xJRAnswered by Jana R. • Maths tutor2493 Views
By multiplying everything in equation 2 by 2, you get 2x + 8y = 34. If you then subtract equation 1 from this you get 5y = 15. Thus y = 3, going back to equation two, and subbing y back in, x + 12 = 17, t...
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