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Maths
GCSE

A point A lies on the line y = 2x^2 - 8x + 2. A has y-coordinate (-4). Find all possible values for the x-coordinate of A.

The point A = (x', y') lies on the line y = 2x2 - 8x +2. And we are given that y' = -4.Therefore we have tha...

Answered by Hasnat K. Maths tutor
2275 Views

A line intercepts point A at (4,4) and point B (8,12). Find the gradient and the intercept of the line.

First, calculate the gradient of the line (m) using the equation using dy / dx.m = dy / dx = (y_2 - y_1) / (x_2 - x_1) = (12 - 4) / (8 - 4) = 8 / 4 = 2.As you now know the gradient of the line and points ...

Answered by Alex F. Maths tutor
2124 Views

ABC is a right-angled triangle (B being the right angle). Is AB=12 and BC=9, What is Angle A? (3.s.f.)

If you having trouble visualising it, try drawing a diagram. Start with SohCahToa. As A is opposite side BC=9, Opposite =9 As AB=12 is adjacent to A, Adjacent=12 Both opp...

Answered by Catherine P. Maths tutor
2214 Views

A is (2,12) and B is (8,2). What is the midpoint of AB?

To find the midpoint we add both x coordinates together and divide by 2. 2+8= 10, 10÷2 = 5 We then add both of the y coordinates together and divide by 2. 12+2 = 14, 14÷2 = 7Then we are given the coord...

Answered by Madelaine D. Maths tutor
10327 Views

Solve (2x+3)(4x-2)=0

To solve a simulatious equation, you should place the contents of each bracket equal to 0.
so (2x+3)=0 and (4x-2)=0
Lets start with the equation on the left.
2x+3=0
Minus...

Answered by Catherine P. Maths tutor
3389 Views

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