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Maths
GCSE

Solve the simultaneous equations 5x + y = 21 x - 3y = 9

To solve simultaneous equations we want to use only one variable so either x or y. Therefore we need to eliminate (get rid of) one of the variables .If you multiply x - 3y = 9 by 5 you will get 5x - 15y =...

Answered by Amelia H. Maths tutor
14729 Views

Azmol, Ryan and Kim each played a game. Azmol’s score was four times Ryan’s score. Kim’s score was half of Azmol’s score. Write down the ratio of Azmol’s score to Ryan’s score to Kim’s score.

4:1:2

Answered by Keena P. Maths tutor
5641 Views

How do you know whether to use sin, cos or tan to find the angle in a triangle?

You have to look at the where the angle is located and what sides of the triangle relative to the angle you are given. The hypotenuse is always the longest line of the triangle, the opposite is always the...

Answered by Feranmi A. Maths tutor
2526 Views

Solve the simultaneous equations: 3x + 4y = 5 , 2x - 3y = 9

To solve the equations the first step to take is to eliminate one of the variables x or y so we can get the value of it and then substitute it back in to get the value of the other.
One way to do thi...

Answered by Yunis B. Maths tutor
3348 Views

Solve the simultaneous equations: 5x + y =21 and x - 3y = 9.

Rearrange x - 3y = 9 to make x the subject by adding 3y to both sides of the equation, giving x = 9 + 3y. Substitute the value of "x" in the second equation for "9 + 3y", giving: 5(9 ...

Answered by Rebecca S. Maths tutor
12883 Views

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