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Maths
GCSE

Solve the simultaneous equations: (3x+2y=3), (x-y=-4)

3x+2y=3 x-y=-4 First, we want to cancel out either x or y so that all we have left is the one we haven't cancelled and a number. To do this we can add or subtract the two equations, possibly multipl...

Answered by Rohan B. Maths tutor
3197 Views

Which of the following lines is not perpendicular to y=2x+1? (A) y+1/2x=6 (B) 2y=4-x (C) 2x+y=4 (D) y=-1/2(7+x)

First of all, we need to figure out how to tell whether 2 lines are perpendicular. For any equation written in the form 'y=mx+c', the important bit of information we need to answer this question is the va...

Answered by Oliver D. Maths tutor
2739 Views

If two linear equations, y = x + 4 and y = 2x + c, intersect at x = 1, find c.

Draw the two equations, indicating the point of intersections (whiteboard).If the lines intersect at x=1, then at that point the y values of each equation are equivalent. Therefore, x+ 4 = 2x + c.Inputtin...

Answered by Tutor27510 D. Maths tutor
2215 Views

Solve the simultaneous equations: x^2-y=16 and 2y-4=14x

Equations: (1) x^2-y=16 and (2) 2y-4=14xRearrange (2) to give y:2y-4=14x(+4) 2y=14x+4(/2) y=7x+2call the new equation (3) y=7x+2Put (3) into (1):x^2-(7x+2)=16(expand) x^2-7x-2=16(-16) x^2-7x-18=0(Factoris...

Answered by Hollie C. Maths tutor
3270 Views

Rationalise the Denominator: 5+√2/(√3)

To rationalise the denominator without chainging the value of the equation, multiply both the numerator and denominator by the value of the denominator.( (5+√2)/(√3) )*(√3/√3) = ( (5√3)+√6 )/3

Answered by Mohammed A. Maths tutor
2634 Views

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