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Maths
GCSE

Solve the following simultaneous equations to give a value for both x and y: 3x+3y=9 and 2x+3y=5

  1. Subtract the bottom equation from the top equation to get 3x-2x=9-5 (you don't see no y values in this equation as the y's have disappeared and cancelled eachother out as 3y-3y=0)2) So 3x-2x=9-5 equ...
Answered by Amy F. Maths tutor
2779 Views

simplify fully: (3x^2 - 8x -3)/(2x^2 -6x)

First of all, to simplify this fraction, we need to factorise the top and bottom equations. We shall start with the top equation. Now looking at the equation: 3x2 - 8x -3, we know that it's a q...

Answered by Amanda H. Maths tutor
3351 Views

Prove that the product of 3 consecutive integers is divisible by 6

If you set the three consecutive integers to be n, n+1 and n+2, we know that one of the numbers must be divisible by 2 and one must be divisible by 3. For example if you had your three numbers as: 5, 6, 7...

Answered by Shreeya K. Maths tutor
12300 Views

Expand and simplify: 5(x +y) + 3(4x-2y)

I'd first explain how expansion works, and that the first step is to expand the first bracket as shown below:The first bracket expands to: 5x + 5y which equals 5x + 5yThe next step I'd show would...

Answered by Harvey J. Maths tutor
3444 Views

Simplify fully (x^2 + 3x)/(4x + 12)

You should begin by factorising the numerator and denominator, in order to determine what would go into both parts of the fraction.As you can see, x2 and 4x have 'x' in common, and 3x and 12 ha...

Answered by Matthew J. Maths tutor
3191 Views

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