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(3x2 - 8x - 3) / 2x2 - 6x == (3x + 1)(x - 3) / 2x2 - 6x == (3x + 1)(x - 3) / 2x(x-3) == 3x+1 / 2x
(5-x)/2=2x-7 5-x=4x-14 5=5x-14 19=5x x=19/5
First we should find the gradient of the line perpendicular to PQ by rearranging the equation.5x+3y=113y=11-5xy=11/5 -5/3xy= -5/3x + 11gradient is -5/3.We know that the gradients of perpendicular lines mu...
Answer: 16 pens and 7 rubbers
This is a quadratic equation, which contains terms up to x2. All quadratic equations can be written in the form ax2 + bx + c = 0 where a, bJWAnswered by Jennifer W. • Maths tutor3090 Views
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