Top answers

Maths
GCSE

Find all of the roots of the equation y = 3x^3 - 12x

Step 1: Remove the most obvious factor, in this case 3x. y = 3x (x2 - 4) Step 2: Realize (x2 - 4) is the product of two squares and can undergo completing the square to produce ...

VD
Answered by Victoria D. Maths tutor
3169 Views

Josie is paid £1200 per month. She is going to receive an increase of 4% in the amount she is paid. Work out how much money Josie we be paid each month after the increase.

We need to first work out what 4% of £1200 is. 1% of £1200 = £(1200/100) = £12. 1% is £12, so 4%= 4*£12 = £48. She will receive a £48 increase.Adding that on to her original amount, £1200 + £48 = £1248.Fi...

JB
Answered by Jack B. Maths tutor
2634 Views

Find the point(s) of intersection of the graphs y=x^2+4x-21 and x+y=-27 using an algebraic method.

As, at the point of intersection, the values of x and y are the same in each graph (otherwise it wouldn't be a point of intersection!), we can approach the problem as solving a pair of simultaneous equati...

PB
Answered by Peter B. Maths tutor
3246 Views

Circle the number that is closest in value to (1.1)/(0.0204) [From selection of 5, 6, 50, 60] [Edit of 2018 Paper 1 Q4]

To simplify the question, the denominator can be rounded to 0.02 (to find an estimate), which comes out to be 1.1/0.02=55, which suggests that the answer is between 50 and 60, and not the other two.Now, a...

DL
Answered by Doug L. Maths tutor
3182 Views

A sphere has a surface area of 4m^2, radius r. Another sphere has radius 2r. Calculate the Volume of the second sphere in M^3.

The surface area of a sphere can be calculated using Area = 4 x Pi x r^2. Since we know the surface are of the first sphere is 4m^2, we can write: 4 = 4 x Pi x r^2. This simplifies to r^2 = 0.318. Taking ...

FW
Answered by Freddie W. Maths tutor
2736 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences