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Maths
GCSE

Solve the simultaneous equations: 1) 6a+b=11 , 2) 5a-2b=19

To solve, first create a common factor for b by multiplying the 1st equation by 2 to get: 12a+2b=22.Now, add the two equations together to get: (12a+5a) + (2b-2b) = (22+19)which is 17a=41 , when simplifie...

Answered by James T. Maths tutor
3144 Views

A cuboid with a volume of 912cm^3 has the dimensions 4 cm, (x + 2) cm and (x + 9) cm. Find an equation in terms of x and solve to find the dimension.

912 = 4(x+2)(x+9)228 = (x+2)(x+9)228 = x2 + 11x + 180 = x2 + 11x -210using the quadratic formula we obtain x = -10 or x = 21As dimensions must be positive; x must equal 21Hence; the ...

Answered by Carys R. Maths tutor
5182 Views

The perimeter of a right angled triangle is 72cm. The length of its sides are in the ratio 3:4:5. Work out the area of the triangle.

Total perimeter - 72cm. Perimeter - (3+4+5)x -> 72=12x therefore x=6. The area of the triangle is 0.5(3x4x) (because 5x is the longest side) therefore the answer is 0.5(1824) = 216cm^2

Answered by Sam T. Maths tutor
2442 Views

Without expanding any brackets work out the exact solutions of 9(x+3)^2=4

Divide through by 9 giving:(x+3)2 = 4/9 Square root both sides remembering a square root is plus or minus the answer x+3 = +/-sqrt(4/9) sqrt(4/9)=2/3for the first solution x+3 = 2/3 or x = -7/3...

Answered by Thomas B. Maths tutor
11013 Views

Expand the brackets: (3a+3)(a+4)

To expand this, we must multiply each term in both brackets separately and then add all of these terms together. First, multiply the first term in each of the brackets: 3a x a = 3a^2. Next multiply the fi...

Answered by Luke B. Maths tutor
3174 Views

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