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Ms Henderson has two jars of sweets. The jars contain the same number of sweets in total. 25% of the sweets in Jar A are mint. Two fifths of the sweets in Jar B are mint. There are 10 mint sweets in Jar A, how many mint sweets are there in Jar B?

For this question we should be familiar with percentages and their equivalents in fraction. Since they have the same number of sweets, we calculate first the total number of sweets there is in the jars an...

Answered by Pablo M. • Maths tutor

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Solve the simultaneous equations using the substitution method. 2y+x=8 and 1+y=2x.

First point out that it makes sense to solve this system of equations using the substitution method because one of the variables can easily be isolated without multiplication or division.(Step 1:) Label t...

Answered by Chris M. • Maths tutor

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What is the correct answer if you rearrange the following, making "c" the subject? (3c+b)/2 = c + a

(3c+b)/2 = c + a To make c the subject of this equation, we first must get all the c variables together on one side of the equation.To do this, first we shall multiply both sides by 2 to remove it from th...

Answered by Matt B. • Maths tutor

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Solve the simultaneous equations: 3x+2y=22, x=y-1

We can see that x=y-1 and therefore can sub this in our first equation, to give us 3(y-1)+2y=22. If we expand the brackets we than have 3y-3+2y=22 which can be tidied up to give 5y-3=22. If we add 3 to bo...

Answered by Katherine F. • Maths tutor

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