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Maths
GCSE

How do I solve simultaneous equations by substitution?

You can solve simultaneous equations by either substitution or elimination. Say we have the equations:(1) 8y + 6x = 24 and (2) 2y - x = 6SUBSTITUTION METHODFirst, you need to find x in terms of y (or y in...

Answered by Joshua N. Maths tutor
2518 Views

Simplify the following, 125^-2/3

1. The minus sign indicates that the answer is a reciprocal meaning basically 1 over.2. Next, on inspection of the fraction, the 2 on top means that you square the number, times it by itself...

Answered by Cameron B. Maths tutor
2623 Views

Differentiate dy/dx ((2x^3)+(x^2)-(4x)+7)

Differentiate each term in the equation separately then put then put the differentiated equation back together.First we start with (2x3):2 x 3 = 6 and 3-1=2 so we get the differentiated term of...

Answered by Theodora R. Maths tutor
2614 Views

Solve the simultaneous equations: 3x + y = 19 and x - 2y = -3

First rearrange x - 2y = -3 by adding 2y to each side to give x = -3 + 2ySubstitute this into the first eq. to give 3(-3 +2y) + y = 19Expand brackets first: -9 + 6y + y = 19Rearrange and simplify by colle...

Answered by Jessica M. Maths tutor
4598 Views

Solve the following simultaneous equations 7x - 6y =38 and 3x + 9y =-3

To solve these equations you first want to eliminate the same variable from each equation. In this question it is easiest to eliminate Y, to do this we will times equation 1 by 3 to get 21X-18Y=114 and eq...

Answered by Isabelle R. Maths tutor
2959 Views

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