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Maths
GCSE

Solve the simultaneous equations: 5x + y = 21, x - 3y = 9

Call '5x + y = 21' equation 1 and 'x - 3y = 9' equation 2. To solve this, we need the coefficients of x in both equations to be the same or the coefficients of y in both equations to be the same.
Met...

Answered by Basil I. β€’ Maths tutor
4036 Views

Factorise 3x+12

We should start by looking for the highest common factor of the 2 numbers involved in the equation (3&12)If you cannot do this immediately in your head, create a factor tree or list the factors3: 312:...

Answered by Ellis T. β€’ Maths tutor
8066 Views

solve the simultaneous equation x^2 + 2y = 9 , y - x = 3

First we need to find a value for x in terms of y , this can be done by rearranging the second equation y - x = 3 to give x = y - 3. This equation is then substituted into the first equation so tha...

Answered by Sara B. β€’ Maths tutor
2311 Views

Given: 𝑓(π‘₯) = π‘Žπ‘₯^3 + 𝑏π‘₯^2 βˆ’ 3 and 𝑓"(βˆ’2) = 0. If it is further given that the point (βˆ’3; 6) lies on the graph of 𝑓. Show that π‘Ž = 1/3 and 𝑏 = 2.

We start off by finding the first derivative of equation f(x) = ax3 + bx2 - 3: f'(x) = 3ax2 + 2bx. We now take the second derivative of equation f, because we have been to...

Answered by Neil L. β€’ Maths tutor
2218 Views

Solve the simultaneous equations: 2x + y = 18 and x - y = 6

We need to find a value of x to sub into equation 1, so add y to both sides of equation 2: x = 6 + y. Then sub this into the x value of equation 1 and solve to find y: 2(6 + y) + y = 18. 12 + 2y + y = 18....

Answered by Anna W. β€’ Maths tutor
2224 Views

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