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Maths
GCSE

Ed has 4 cards. There is a number on each card. Three of the numbers are 12, 6 and 15. The mean of the numbers is 10. What is the fourth number?

To find the mean you add all the numbers together and divide by the number of numbers. Call the fourth number x. Then we know that (12+6+15+x)/4 =10. then multiply both sides by 4 to get 12+6+15+x=40 whi...

Answered by Sarah P. Maths tutor
8790 Views

Factorise fully 6xyz + 24x^2yz + 18xy^3z^2

So we need to find common factors for each term: 6xyz, 24x2yz and 18xy3z2. Let's start with the numbers. Do the numbers 6, 24 and 18 have a common factor? Yes, 6 . If we t...

Answered by Tom L. Maths tutor
2962 Views

Solve the Simultaneous equation: 6x+3y=13, 14x-9y=9?

First we need to eliminate one of the Variables, to have an equation dependant on one variable. The coefficient for y in equation two is a third of the coefficient of the y in the second equation. Therefo...

Answered by Matthew M. Maths tutor
2730 Views

How to find the longest side of a right-angled triangle if we are given the two other sides?

We can find the longest side of a right angled triangle (also called the hypotenuse) by using Pythagoras' Theorem and considering the lengths of the two other sides given to us. Pythagoras' Theorem is wri...

Answered by Denzel C. Maths tutor
16745 Views

make x the subject of 5(x-3) = y(4-3x)

step 1 ; expand the brackets5x - 15 = 4y - 3xystep 2 ; group together x values on one side5x + 3xy = 4y + 15step 3 ; single out xx (5+3y) = 4y +15step 4 ; make x the subjectx = (4y + 15) / (5+3y)

Answered by Sofia A. Maths tutor
4420 Views

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