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To approach a problem like this, we must first break down our number into a multiplication of prime factors (i.e. we can make our number by multiplying numbers 2,3,5,7 etc together). This is best done wit...
Quadratic equations are always given in the form ax2 +bx +c. One way of solving (finding values of x) and therefore factorising is to use the ...
You make simultaneous equations. 1.) 3T+2C=7.82.) 5T+4C=14.2Then you make either the C or the T coefficient equal in both equations. I choose to make the C coefficients the same. So I multiplied equation ...
In this sequence, there is no common difference between one term and the next making it more challenging to solve. However, if you look at the terms closely, you can see that each term is the sum of the p...
From x : y = 7 : 4 work out an expression for x: x = y (7/4) and substitute into x + y = 88: y(7/4 + 1) = 88y( 11/4) = 88 y = 88 (4/11) = 8 x 4 = 24substitute this into x + y = 88 to get x = 88 - 24 = 64....
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