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Maths
GCSE

How do I approach simultaneous equations with 2 unknowns?

The two common ways to approach them is either by substitution or addition/subtraction. Firstly, for substitution, rearrange one of your equation so that one of the unknowns becomes the subject and then ...

Answered by Louis S. Maths tutor
1968 Views

Solve the simultaneous equations 2x + 3y = 19 , 3x + y = 11

Rearrange to make the y component the subject3y = 19 - 2x , y = 11 - 3xMultiply the second equation by 33y = 33 - 9xEquate to each other19 - 2x = 33 - 9xRearrange7x = 14Divide by 7x = 2Substitute x=2 into...

Answered by David B. Maths tutor
3566 Views

Write x^2 + 4x + 18 in the form (x + a)^2 + b, where a and b are constants to be determined.

(x + 2)^2 + 14. a = 2, b = 14

Answered by Danqing H. Maths tutor
3250 Views

The functions f and g are such that f(x)=5x+2 and g(x)=-x-4. a) Find fg(x). b) Find ff(x). c) Solve fg(x) = ff(x).

a) fg(X) = 5(-x-4)+2 = -5x-20+2 = -5x-18b) ff(X) = 5(5x+2)+2 = 25x+10+2 =25x+12c) 25x+12=-5x-18 25x+5x=-18-12 30x=-30 x=-1


Answered by Maria A. Maths tutor
3809 Views

Find g(f(x)) where g(x)=2x+4 and f(x)=x^2+1.

With functions of functions you work from the inside out, so you substitute the function f(x) for the x in g(x). We know that f(x)=x2+1 and g(x)=2x+4. In this question you therefore replace the...

Answered by Georgina M. Maths tutor
2012 Views

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