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When looking at this equation, we need to think of two numbers that multiply together to give 12 and have a difference of one. We can rewrite the equation as the following: (x-4)(x+3) = 0 Solving for x:Th...

3(x+1) - 2(x-1) = 1(x-1)(x+1)3x + 3 - 2x + 2 = x² - 1x² - x - 6 = 0(x - 3)(x + 2) = 0x = 3 x = -2

Begin by setting up the equations simultaneously. To make it easier we can label the equations (1) and (2)3y-2x=11 (1)y+x=12 (2)We then need to make the values of y or the values of x equal in both equati...

The quadratic formula is used to find the roots of a quadratic equation which comes in this form:

y = ax² + bx + c

By finding the roots, we mean that we find the values of...

Expand brackets: 8p-6. Move all values to one side: p - 8p + 15 + 6 = 0. Subtract p values and add normal numbers: -7p + 21 = 0. Move p values to other side: 21 = 7p. Divide through by 7: p = 21/7. p = 3....