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Maths
GCSE

Solve these simultaneous equations (1) 12x + 3.5y = 32 (2) 8x + 3y = 24

Make the like terms equate by multiplying (1)*2 and (2)*3, ((1)*2) 24x+7y=64, ((2)*3) 24x+9y=72, Take one away from the other to remove the x term and solve for y, (24x+9y=72) - (24x+7y=64), 2y=8 y=4, Su...

Answered by Karen J. Maths tutor
2137 Views

A scalene triangle has side lengths a=xcm, b=10cm and c=15cm. The angle A=105 degrees is opposite side a. Using the cosine rule, find the value of x to 3 s.f.

The cosine rule= a2 = b2+c2-2bcCos(A)a2= 102+152-(2x10x15xCos(105))a2= 402.65...Square root of ans.a= 20.07x=20.1cm

Answered by Laurie R. Maths tutor
2384 Views

For all values of x, f(x) = (x + 1)^2 and g(x) = 2(x-1). Show that gf(x) = 2x(x + 2) and find g^-1(7)

gf(x) means you are applying the function f to x (giving you f(x)) and then you are applying the function g to f(x). Since g(x) = 2(x-1), g(f(x)) =2(f(x)-1). This means after substitution, gf(x) = 2((x+1)...

Answered by Arya P. Maths tutor
7849 Views

Solve: 3X - 5 = Y 2X +2 = Y +3

2X +2 = Y + 3 2X -1 = Y3X -5 = Y3X -5 = 2X -1 X -5 = -1 X = 43X -5 =Y 3(4) -5 = Y12 - 5 = Y7 = Y
X = 4 Y = 7

Answered by Tutor516653 D. Maths tutor
2195 Views

If f(x)=(x-2)^2, determine the gradient of the tangent to the curve f(x) at x=-2.

Firstly, we will need to determine f'(x) which is the derivative of the function and will give us the gradient at a point. This is easiest done but multiplying out the brackets of f(x) to get the function...

Answered by Cameron G. Maths tutor
2515 Views

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