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If we knew (x² + 6x) to be the first two terms of a perfect square expression, but not the constant term that would follow, we can work it out. We would use the fact that the expression can be ...

First, we need to factorise the denominator and therefore we use this formula: x_1,2 =[ -b + sqrt(b² -4 a c) ]/ (2a). You obtain two roots, x = 2 and x=3 and the integration is simpli...

We have derivative rules. Some of them involve:If f(x)= (x)^a=> f'(x)= a*x^a-1If f(x)= ln x=> f'(x)= 1/xIf f(x)= sin x=> f'(x)=cos xTherefore, f(x)= 6y+1/x+cos x

Claim: For any prime p: (p-1)! = -1 (mod p)Proof: For p=2: 1! = 1 so the equality obviously holds. Therefore, we need to consider cases when p is odd.
Let's consider set: {1, ... , p-1}...

First write out the unit vectors in I, j, and k form. Then put these values into a matrix. Then find the determinant of the matrix. Then you will have reached your answer. I couldn't figure out how to sho...