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The moment of a couple is the force times the perpendicular distance between the lines of action of the force.
Horizontal: T1 sin θ1 = T2 sin θ2Vertical: T1 cos θ1 + T2 cos θ2 = w
A stationary point is a point where dy/dx = 0.First we need to find dy/dx. This is done by differentiating y term by term to get dy/dx = 3x^2 - 6x - 9.Setting this equal to zero, we need to solve 3x^2 - 6...
rearrange by taking away 2 and adding 1
x2 + 14x + 22 = 4x -21) First you should arrange the equation into the format ax2 + bc + c = 0. This gives x2 + 10x + 24 =02) Factorise into (x+n)(x+m) = 0. To work...
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